15^2+36^2=x^2

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Solution for 15^2+36^2=x^2 equation:



15^2+36^2=x^2
We move all terms to the left:
15^2+36^2-(x^2)=0
We add all the numbers together, and all the variables
-1x^2+1521=0
a = -1; b = 0; c = +1521;
Δ = b2-4ac
Δ = 02-4·(-1)·1521
Δ = 6084
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{6084}=78$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-78}{2*-1}=\frac{-78}{-2} =+39 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+78}{2*-1}=\frac{78}{-2} =-39 $

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